js获取页面传来的参数

    function GetQueryString(name) {  
       var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)","i");  
       var r = window.location.search.substr(1).match(reg);  
       if (r!=null) return (r[2]); return null;  
    }  
      
    var sname = GetQueryString("name");  
    if(sname!=null)  
    {  
        var sname_ = decodeURIComponent(sname);  
        alert(sname_);  
    }  

测试

abcd.html?name=xyz

应该弹出xyz