python pycurl验证basic和digest认证的方法
时间：2021-09-25 08:18:04|栏目：Python代码|点击： 次
简介
pycurl类似于Python的urllib，但是pycurl是对libcurl的封装，速度更快。
本文使用的是pycurl 7.43.0.1版本。
Apache下配置Basic认证
生成basic密码文件
htpasswd -bc passwd.basic test 123456
开启mod_auth_basic
LoadModule auth_basic_module modules/mod_auth_basic.so
配置到具体目录
<Directory "D:/test/basic"> AuthName "Basic Auth Dir" AuthType Basic AuthUserFile conf/passwd.basic require valid-user </Directory>
重启Apache
Apache下配置Digest认证
生成Digest密码文件
htdigest -c passwd.digest "Digest Encrypt" test
开启mod_auth_digest
LoadModule auth_digest_module modules/mod_auth_digest.so
配置到具体目录
<Directory "D:/test/digest"> AuthType Digest AuthName "Digest Encrypt" # 要与密码的域一致 AuthDigestProvider file AuthUserFile conf/passwd.digest require valid-user </Directory>
重启Apache
验证Basic认证
# -*- coding: utf-8 -*-
import pycurl
try:
from io import BytesIO
except ImportError:
from StringIO import StringIO as BytesIO
buffer = BytesIO()
c = pycurl.Curl()
c.setopt(c.URL, 'http://test/basic/')
c.setopt(c.WRITEDATA, buffer)
c.setopt(c.HTTPAUTH, c.HTTPAUTH_BASIC)
c.setopt(c.USERNAME, 'test')
c.setopt(c.PASSWORD, '123456')
c.perform()
print('Status: %d' % c.getinfo(c.RESPONSE_CODE))
print(buffer.getvalue())
c.close()
验证Digest认证
# -*- coding: utf-8 -*-
import pycurl
try:
from io import BytesIO
except ImportError:
from StringIO import StringIO as BytesIO
buffer = BytesIO()
c = pycurl.Curl()
c.setopt(c.URL, 'http://test/digest/')
c.setopt(c.WRITEDATA, buffer)
c.setopt(c.HTTPAUTH, c.HTTPAUTH_DIGEST)
c.setopt(c.USERNAME, 'test')
c.setopt(c.PASSWORD, '123456')
c.perform()
print('Status: %d' % c.getinfo(c.RESPONSE_CODE))
print(buffer.getvalue())
c.close()
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