python 找出list中最大或者最小几个数的索引方法

nums = [1,8,2,23,7,-4,18,23,24,37,2]
result = map(nums.index, heapq.nlargest(3, nums))
temp=[]
Inf = 0
for i in range(3):
  temp.append(nums.index(max(nums)))
  nums[nums.index(max(nums))]=Inf
result.sort()
temp.sort()
print(result)
print(temp)

[3, 8, 9]
[3, 8, 9]

nums = [1,8,2,23,7,-4,18,23,23,37,2]

[3, 3, 9]
[3, 7, 9]