php中判断一个字符串包含另一个字符串的方法

if(strpos('www.jb51.net','jb51') !== false){ 
 echo '包含jb51'; 
}else{
 echo '不包含jb51'; 
}

<?php 
$name = "001x.gif"; 
$pan = "x"; 
$con = explode($pan,$name); 
if (count($con)>1): 
echo $name."中包含".$pan; 
else: 
echo $name."中没有包含".$pan; 
endif; 
?> 

<?php
  /*如手册上的举例*/
  $email = 'user@example.com';
  $domain = strstr($email, '@');
  echo $domain;
  // prints @example.com
?>