Python计算两个矩形重合面积代码实例
时间：2021-02-27 14:30:43|栏目：Python代码|点击： 次
这篇文章主要介绍了Python 实现两个矩形重合面积代码实例,文中通过示例代码介绍的非常详细，对大家的学习或者工作具有一定的参考学习价值,需要的朋友可以参考下
代码如下
计算两个矩形的重合面积
import math
x1, y1, x2, y2 = input().split(" ")
x1, y1, x2, y2=int(x1), int(y1), int(x2), int(y2)
# print(x1, y1, x2, y2)
x1,x2 = min(x1,x2),max(x1,x2)
y1,y2= min(y1,y2),max(y1,y2)
# print(x1, y1, x2, y2)
x3, y3, x4, y4 = input().split(" ")
x3, y3, x4, y4 = int(x3), int(y3), int(x4), int(y4)
x3,x4 = min(x3,x4),max(x3,x4)
y3,y4 = min(y3,y4),max(y3,y4)
# print(x3, y3, x4, y4)
if (x2<=x3 or x4<=x1) and (y2 <= y3 or y4<=y1):
print(0)
else:
lens = min(x2, x4) - max(x1, x3)
wide = min(y2, y4) - max(y1, y3)
print(lens*wide)
字符串重叠输出
import string
in_str = input()
nums = string.digits
a = ""
strs = ""
num = ""
for i in range(len(in_str)):
if in_str[i] not in nums:
a = a+in_str[i]
else:
if i == len(in_str)-1 or (in_str[i+1] not in nums):
num = int(num + in_str[i])
strs = strs + a*num
a=""
num=""
else:
num = num + in_str[i]
print(strs)
