Python 判断时间是否在时间区间内的实例

# 给定两个时间来比较下
>>> from datetime import datetime
>>> a=datetime.now()
>>> b=datetime.now()
>>> a
datetime.datetime(2019, 6, 5, 14, 3, 28, 396610)
>>> b
datetime.datetime(2019, 6, 5, 14, 3, 35, 226784)
>>> a<b
True
>>> b<a
False

from dateutil.parser import parse
NOW = datetime.now()
gt = parse("2019-6-3")
lt = parse("2019-6-8")
gt<NOW<lt

from interval import Interval
a = Interval(s1, e1)
b = Interval(s2, e2)
a in b

  /**
   * 判断当前时间是否在[startTime, endTime]区间，注意时间格式要一致
   *
   * @param nowTime 当前时间
   * @param startTime 开始时间
   * @param endTime 结束时间
   */
  public static boolean isEffectiveDate(Date nowTime, Date startTime, Date endTime) {
    if (nowTime.getTime() == startTime.getTime()
        || nowTime.getTime() == endTime.getTime()) {
      return true;
    }
    Calendar date = Calendar.getInstance();
    date.setTime(nowTime);
 
    Calendar begin = Calendar.getInstance();
    begin.setTime(startTime);
 
    Calendar end = Calendar.getInstance();
    end.setTime(endTime);
 
    if (date.after(begin) && date.before(end)) {
      return true;
    } else {
      return false;
    }
  }